TensorPlay
API reference
latest (dev)
Copy
View Markdown

Latest development documentation · Updated 2026-10-15

tensorplay.autograd.functional API

Functions 6

#

hessian

functionFull reference ↗
tensorplay.autograd.functional.hessian(func, inputs, create_graph=False, strict=False, vectorize=False, outer_jacobian_strategy='reverse-mode')[source]

Compute the Hessian of a given scalar function.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a Tensor with a single element.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • create_graph (bool, optional) – If True, the Hessian will be computed in a differentiable manner. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the hessian for said inputs, which is the expected mathematical value. Defaults to False.

  • vectorize (bool, optional) – Not supported by this engine yet; passing True raises NotImplementedError.

  • outer_jacobian_strategy (str, optional) – Only "reverse-mode" is supported; forward-mode AD raises NotImplementedError.

Returns:

if there is a single input, this will be a single Tensor containing the Hessian for the input. If it is a tuple, then the Hessian will be a tuple of tuples where Hessian[i][j] will contain the Hessian of the ith input and jth input with size the sum of the size of the ith input plus the size of the jth input. Hessian[i][j] will have the same dtype and device as the corresponding ith input.

Return type:

Hessian (Tensor or a tuple of tuple of Tensors)

Example

>>> def pow_reducer(x):
...     return x.pow(3).sum()
>>> inputs = tensorplay.rand(2, 2)
>>> hessian(pow_reducer, inputs)
tensor([[[[5.2265, 0.0000],
          [0.0000, 0.0000]],
         [[0.0000, 4.8221],
          [0.0000, 0.0000]]],
        [[[0.0000, 0.0000],
          [1.9456, 0.0000]],
         [[0.0000, 0.0000],
          [0.0000, 3.2550]]]])
#

hvp

functionFull reference ↗
tensorplay.autograd.functional.hvp(func, inputs, v=None, create_graph=False, strict=False)[source]

Compute the dot product between the scalar function’s Hessian and a vector v at a specified point.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a Tensor with a single element.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • v (tuple of Tensors or Tensor) – The vector for which the Hessian vector product is computed. Must be the same size as the input of func. This argument is optional when func’s input contains a single element and (if it is not provided) will be set as a Tensor containing a single 1.

  • create_graph (bool, optional) – If True, both the output and result will be computed in a differentiable way. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the hvp for said inputs, which is the expected mathematical value. Defaults to False.

Returns:

tuple with:

func_output (tuple of Tensors or Tensor): output of func(inputs)

hvp (tuple of Tensors or Tensor): result of the dot product with the same shape as the inputs.

Return type:

output (tuple)

Example

>>> def pow_reducer(x):
...     return x.pow(3).sum()
>>> inputs = tensorplay.rand(2, 2)
>>> v = tensorplay.ones(2, 2)
>>> output = hvp(pow_reducer, inputs, v)
>>> output[0]
tensor(0.1448)
>>> output[1]
tensor([[2.0239, 1.6456],
        [2.4988, 1.4310]])

Note

This function is significantly slower than vhp due to backward mode AD constraints. If your function is twice continuously differentiable, then hvp = vhp.t(). So if you know that your function satisfies this condition, you should use vhp instead that is much faster with the current implementation.

#

jacobian

functionFull reference ↗
tensorplay.autograd.functional.jacobian(func, inputs, create_graph=False, strict=False, vectorize=False, strategy='reverse-mode')[source]

Compute the Jacobian of a given function.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a tuple of Tensors or a Tensor.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • create_graph (bool, optional) – If True, the Jacobian will be computed in a differentiable manner. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the jacobian for said inputs, which is the expected mathematical value. Defaults to False.

  • vectorize (bool, optional) – Not supported by this engine yet; passing True raises NotImplementedError.

  • strategy (str, optional) – Set to "reverse-mode" (default) or "forward-mode". Forward-mode AD is not supported by this engine yet; passing it raises NotImplementedError.

Returns:

if there is a single input and output, this will be a single Tensor containing the Jacobian for the linearized inputs and output. If one of the two is a tuple, then the Jacobian will be a tuple of Tensors. If both of them are tuples, then the Jacobian will be a tuple of tuple of Tensors where Jacobian[i][j] will contain the Jacobian of the ith output and jth input and will have as size the concatenation of the sizes of the corresponding output and the corresponding input and will have same dtype and device as the corresponding input.

Return type:

Jacobian (Tensor or nested tuple of Tensors)

Example

>>> def exp_reducer(x):
...     return x.exp().sum(dim=1)
>>> inputs = tensorplay.rand(2, 2)
>>> jacobian(exp_reducer, inputs)
tensor([[[1.4917, 2.4352],
         [0.0000, 0.0000]],
        [[0.0000, 0.0000],
         [2.4369, 2.3799]]])
#

jvp

functionFull reference ↗
tensorplay.autograd.functional.jvp(func, inputs, v=None, create_graph=False, strict=False, mode='forward')[source]

Compute the dot product between the Jacobian of the given function at the point given by the inputs and a vector v.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a tuple of Tensors or a Tensor.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • v (tuple of Tensors or Tensor) – The vector for which the Jacobian vector product is computed. Must be the same size as the input of func. This argument is optional when the input to func contains a single element and (if it is not provided) will be set as a Tensor containing a single 1.

  • create_graph (bool, optional) – If True, both the output and result will be computed in a differentiable way. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the jvp for said inputs, which is the expected mathematical value. Defaults to False.

Returns:

tuple with:

func_output (tuple of Tensors or Tensor): output of func(inputs)

jvp (tuple of Tensors or Tensor): result of the dot product with the same shape as the output.

Return type:

output (tuple)

Example

>>> def exp_reducer(x):
...     return x.exp().sum(dim=1)
>>> inputs = tensorplay.rand(4, 4)
>>> v = tensorplay.ones(4, 4)
>>> jvp(exp_reducer, inputs, v)
(tensor([6.3090, 4.6742, 7.9114, 8.2106]),
 tensor([6.3090, 4.6742, 7.9114, 8.2106]))
>>> def adder(x, y):
...     return 2 * x + 3 * y
>>> inputs = (tensorplay.rand(2), tensorplay.rand(2))
>>> v = (tensorplay.ones(2), tensorplay.ones(2))
>>> jvp(adder, inputs, v)
(tensor([2.2399, 2.5005]),
 tensor([5., 5.]))
mode (str, optional): “forward” runs func once with the dual-tensor

engine and propagates tangents op by op (the default; func must be written with operators supported by forward-mode). “reversed” computes the jvp via the double backwards trick and works for any twice-differentiable func.

#

vhp

functionFull reference ↗
tensorplay.autograd.functional.vhp(func, inputs, v=None, create_graph=False, strict=False)[source]

Compute the dot product between vector v and Hessian of a given scalar function at a specified point.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a Tensor with a single element.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • v (tuple of Tensors or Tensor) – The vector for which the vector Hessian product is computed. Must be the same size as the input of func. This argument is optional when func’s input contains a single element and (if it is not provided) will be set as a Tensor containing a single 1.

  • create_graph (bool, optional) – If True, both the output and result will be computed in a differentiable way. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the vhp for said inputs, which is the expected mathematical value. Defaults to False.

Returns:

tuple with:

func_output (tuple of Tensors or Tensor): output of func(inputs)

vhp (tuple of Tensors or Tensor): result of the dot product with the same shape as the inputs.

Return type:

output (tuple)

Example

>>> def pow_reducer(x):
...     return x.pow(3).sum()
>>> inputs = tensorplay.rand(2, 2)
>>> v = tensorplay.ones(2, 2)
>>> output = vhp(pow_reducer, inputs, v)
>>> output[0]
tensor(0.5591)
>>> output[1]
tensor([[1.0689, 1.2431],
        [3.0989, 4.4456]])
#

vjp

functionFull reference ↗
tensorplay.autograd.functional.vjp(func, inputs, v=None, create_graph=False, strict=False)[source]

Compute the dot product between a vector v and the Jacobian of the given function at the point given by the inputs.

Parameters:
  • func (function) – a Python function that takes Tensor inputs and returns a tuple of Tensors or a Tensor.

  • inputs (tuple of Tensors or Tensor) – inputs to the function func.

  • v (tuple of Tensors or Tensor) – The vector for which the vector Jacobian product is computed. Must be the same size as the output of func. This argument is optional when the output of func contains a single element and (if it is not provided) will be set as a Tensor containing a single 1.

  • create_graph (bool, optional) – If True, both the output and result will be computed in a differentiable way. Note that when strict is False, the result can not require gradients or be disconnected from the inputs. Defaults to False.

  • strict (bool, optional) – If True, an error will be raised when we detect that there exists an input such that all the outputs are independent of it. If False, we return a Tensor of zeros as the vjp for said inputs, which is the expected mathematical value. Defaults to False.

Returns:

tuple with:

func_output (tuple of Tensors or Tensor): output of func(inputs)

vjpval (tuple of Tensors or Tensor): result of the dot product with the same shape as the inputs.

Return type:

output (tuple)

Example

>>> def exp_reducer(x):
...     return x.exp().sum(dim=1)
>>> inputs = tensorplay.rand(4, 4)
>>> v = tensorplay.ones(4)
>>> vjp(exp_reducer, inputs, v)
(tensor([5.7817, 7.2458, 5.7830, 6.7782]),
 tensor([[1.4458, 1.3962, 1.3042, 1.6354],
        [2.1288, 1.0652, 1.5483, 2.5035],
        [2.2046, 1.1292, 1.1432, 1.3059],
        [1.3225, 1.6652, 1.7753, 2.0152]]))

On this page

Ask DeepWiki